Question 1207294

 the equation of the line in standard form 

{{{ax+by=c}}}


given:

 y-intercept {{{3}}} => point ({{{0}}},{{{3}}})

 a slope of  {{{m=-2/3}}}


using point slope form we have


{{{y-y[1]=m(x-x[1])}}}....substitute given values

{{{y-3=-(2/3)(x-0)}}}

{{{y-3=-(2/3)x}}}

{{{y=-(2/3)x+3}}}...both sides multiply by {{{3}}}

{{{3y=-2x+9}}}

{{{2x+3y=9}}} => your equation


{{{ graph( 600, 600, -10, 10, -10, 10, -(2/3)x+3) }}}