Question 1207278
The given equation is cos(2x+10)=sin(x+20)
We have cos(90-theta)=sin(theta)
Substituting the values we get,
90-theta=2x+10........(1)
theta=x+20............(2)
We have simultaneous equations in two unknowns.
Adding equations 1 and 2 we get,
90-theta+theta=2x+10+x+20
90=3x+30
3x+30=90
3x=90-30=60
x=12
The answer is x=12.