Question 1207269
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the line parrallel to y=6x-2 through (1,-3)
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For parallel, the slope is the same   (6).
The y-intercept is different.


{{{y=6x+b}}}

{{{y-6x=b}}}

{{{b=y-6x}}}

substituting the point given, required to be on the looked-for line:

{{{b=-3-6*1}}}

{{{b=-9}}}


Equation for asked-for line:  {{{highlight(y=6x-9)}}}



Your other exercise,  for perpendicular, you want a slope to be negative reciprocal of the given slope.  You do the rest.