Question 1207181
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How fast would you have to go to pass a car going 45 mph 
from 50 ft behind to 50 ft in front in less than 1/8 mile
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<pre>
Let v be the speed of your car, which is required to pass another car as described.

Your car should travel 1/8 mile (which is the same as 0.125 mile) in the same time
as the other car will travel 100 ft less distance.


100 ft is {{{100/5280}}} of a mile, or 0.018939394 of a mile.


So, the other car covers the distance (0.125-0.018939394) = 0.106060606 of a mile
in the same time as your car covers 0.125 of a mile.


Thus, we can write this time equation

    {{{0.106060606/45}}} = {{{0.125/v}}},


saying that the time is the same for both cars.


From this equation, you get  v = {{{(0.125*45)/0.106060606}}} = 53.03571432 miles per hour.


Rounding to three decimals, the answer is 53.036 miles per hour.


<U>ANSWER</U>.  The speed of your car should be about 53.036 miles per hour (or higher).
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Solved.