Question 1207174
.
In an isosceles triangle, the measure of one base angle is 15 degrees more 
than twice the measure of the vertex angle. Find the measures of all three angles
~~~~~~~~~~~~~~~~~~


<pre>
Let x be the measure of the vertex angle, in degrees.

Then the angles at the base are (2x+15) degrees each; they are congruent.


The sum of angles is 180 degrees

    (2x+15) + (2x+15) + x = 180

     5x + 30 = 180

     5x = 180 - 30 = 150

     5x = 150

      x = 150/5 = 30.


<U>ANSWER</U>.  The vertex angle is 30 degrees.  The angles at the base are {{{(180-30)/2}}} = 75 degrees each.
</pre>

Solved.