Question 1207030
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Answer: <font color=red>(-3, -3)</font>


Explanation


Compare y=3x^2+18x+24 to the template y = ax^2+bx+c
a = 3
b = 18
c = 24


The vertex is located at (h,k)
Let's determine the x coordinate of the vertex.
h = -b/(2a)
h = -18/(2*3)
h = -3


Plug this into the equation to find the y coordinate of the vertex.
y = 3x^2+18x+24
y = 3*(-3)^2+18(-3)+24
y = -3


The vertex is located at (h,k) = <font color=red>(-3, -3)</font>


We go from vertex form
y = a(x-h)^2 + k
to
y = 3(x-(-3))^2 + (-3)
y = 3(x + 3)^2  - 3
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