Question 1206928
<pre>
Sketch a figure and solve each right triangle ABC with right angle at C. given that:
1. A = 15° and c = 37
2. B = 64° and c = 19.2
3. A = 15° and c = 25
4. A = 45° and c = 16
5. B = 56° and c = 16

Law of Sines? Totally UNNECESSARY here.

1. A = 15° and c = 37
   GIVEN: A triangle with angle A being 15<sup>o</sup>, hypotenuse AB (c) being 37 units, OPPOSITE
   side, BC (a), and ADJACENT side AC (b).

   {{{matrix(2,3, cos (A), "=", A/H, cos (15^o), "=", b/37)}}} 
Side <font color = red><font size = 4><b>b (AC) = 37 * cos (15<sup>o</sup>) = 35.74 units</font></font></b> ------ Cross-multiplying
Needless to say, <font color = red><font size = 4><b>Acute angle B = 75<sup>o</sup> (90<sup>o</sup> - 15<sup>o</sup>)</font></font></b>
Side<font color = red><font size = 4><b> a (BC) = 37 * cos (90 - 15)<sup>o</sup> = 37 * cos (75<sup>o</sup>) = 9.58 units.</font></font></b>

Apply same concept to the rest, sketching EACH triangle as you go along!!</pre>