Question 1207010
<pre>
10 PM is 6 hours after 4 PM and 2 hours after 8 PM
1st train's speed is r mph
2nd train's speed is r+112 mph

Make a chart:

                   |rate |time |distance|
1st train at 10 PM |  r  |  6  |   6r   |
2nd train at 10 PM |r+112|  2  |2(r+112)|

Set the distances equal.

{{{6r}}}{{{""=""}}}{{{2(r+112)}}}

Solve that for r and you'll get r = 56 mph for the 1st train.
Add 112 to 56 and you'll get 168 mph for the 2nd train.

Can a train go that fast?  Could it stay on the rails? LOL  

Edwin</pre>