Question 1206959
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Water is leaking fron a tank at a constant rate. At 230pm the tank is 3/5 full.
At 325pm the tank was 2/7 full. At what time will the tank be empty.
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<pre>
The volume of water leaked from the tank from 2:30 pm to 3:25 pm is the difference

      {{{3/5}}} - {{{2/7}}} = simplify using common denominator = {{{(3*7)/35 - (2*5)/35}}} = {{{21/35 - 10/35}}} = {{{11/35}}}


of the total tank volume.  The time elapsed from 2:30 pm to 3:25 pm is 55 minutes.


So, every 5 minutes, the leaking volume is  {{{1/35}}}  of the tank volume.


At 3:25 pm the tank is/was  {{{2/7}}} = {{{10/35}}}  full.


Hence, the tank will be empty in 5*10 = 50 minutes after 3:25 pm, which is 4:15 pm.    <U>ANSWER</U>
</pre>

Solved.


The solution requires a bit of manipulations with fractions, &nbsp;a bit of common sense,
basic skills of understanding and manipulating with reading clock face, &nbsp;and a bit of accuracy.


Nothing more. &nbsp;&nbsp;Even using equations is not necessary.