<PRE><B>Question 116166</B>
THE MAXIMUM AREA OF A RECTANGLE IS IN THE FORM OF A SQUARE.
SEING AS THERE IS ALREADY ON SIDE YOU NEED TO FIND THREE ADDITIONAL SIDES OF EQUAL LENGTH.
20 PIECES OF 2.8 METERS=56 METERS
56/3=18 2/3 METERS IS THE LENGTH OF EACH OF THE 3 SIDES.
THUS THE ENCLOSED AREA=56/3*3=56 M^2.
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40 PIECES=40*2.8=112 METERS.
112/3=37 1/3 METERS IS THE LENGTH OF EACH OF THE 3 SIDES.
THUS THE ENCLOSED AREA=112/3*3=112 M^2.  
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