Question 1206849
<pre>
t1=-3. tn=4-2t^n-1 find t4

NO NEED TO REPOST, as the OTHER PERSON suggests!

                      {{{matrix(1,3, t[1], "=", - 3)}}}           {{{matrix(1,3, t[n], "=", 4  -  2t[n - 1])}}}
<font color = red><font size = 3>     =================            ================           =================</font></font>
     {{{matrix(1,3, highlight(t[2]), "=", 4 - 2t[2 - 1])}}}            {{{matrix(1,3, highlight(t[3]), "=", 4 - 2t[3 - 1])}}}           {{{matrix(1,3, highlight_green(t[4]), "=", 4 - 2t[4 - 1])}}}
         {{{matrix(3,2, "=", 4  -  2t[1],
"=", 4 - 2(- 3),
"=", 4 + 6
)}}}                {{{matrix(3,2, "=", 4  -  2t[2],
"=", 4 - 2(10),
"=", 4 - 20
)}}}                {{{matrix(3,2, "=", 4  -  2t[3],
"=", 4 - 2(- 16),
"=", 4 + 32
)}}}
     {{{matrix(1,3, highlight(t[2]), "=", highlight(10))}}}                  {{{matrix(1,3, highlight(t[3]), "=", highlight(- 16))}}}                {{{matrix(1,3, highlight_green(t[4]), "=", highlight_green(36))}}}</pre>