Question 1206861
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Looking ahead to see that the second of the four consecutive odd numbers is squared, I will guess that the algebra required to solve the problem might be easiest if I let x be the second number.  So the four consecutive odd numbers are x-2, x, x+2, and x+4.<br>
Then the problem says<br>
{{{(x-2)(x+4)-x^2=22}}}
{{{x^2+2x-8-x^2=22}}}
{{{2x-8=22}}}
{{{2x=30}}}
{{{x=15}}}<br>
The second number is x=15; the four numbers are then 13, 15, 17, and 19.<br>
ANSWER: 13, 15, 17, and 19<br>
CHECK: (13*19)-15^2=247-225=22<br>