<PRE><B>Question 1206861</B>
given four consecutive odd numbers.
n, n+2, n+4, n+6

when the square of the second number is subtracted from the product of the first and last numbers,the answer is 22.
n(n+6) - (n+2)^2 = 22

find them. 
(n^2 + 6n) - (n^2 + 4n + 4) = 22
Combine like terms, removing bracket on the 2nd expression changes sign to -
n^2 - n^2 + 6n - 4n - 4 = 22
2n = 22 + 4
2n = 26
n = 13

The 4 numbers 13, 15, 17, 19

Check:
13*19 - 15^2 =
247 - 225 = 22
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