Question 1122533
1. The nth term of a sequence is given by the formula: n/2(3n^2+1), find the 6th term.

{{{a(n) = (n/2)(3n^2+1)}}}

{{{a(6) = (6/2)(3*6^2+1)}}}

{{{a(6) = 3*(3*36+1)}}}

{{{a(6) = 3*109)}}}

a(6) = 327

2. The nth term of a sequence is denoted by 3n(2^n-1), find the sum of the first 5 terms
a(n) =3n(2^n-1)

a(1) = 3
a(2)= 18
a(3)= 63
a(4)=180
a(5)= 465
Add them up

3. What is the value of X for which the expression is not defined: 2x+3/x2-16?