<PRE><B>Question 1206817</B>
Given AB ||PQ 

Therefore triangles PQR and PAB are similar triangles  ( by AA test)

THE RATIOS OF CORRESPONDING SIDES OF SIMILAR TRIANGLES ARE EQUAL.

PA+AQ=PQ
PB+BQ=PQ

PA/PQ = PB/PR

(3x-2 )/(3x+3) =(5x+2)/(5x+12)

(3x-2)(5x+12) = (3x+3)(5x+2)

3x(5x+12)-2(5x+12) = 3x(5x+2)+3(5x+2)

15x^2+36x -10x-24 =15x^2+6x+15x+6

26x-24 = 21x+6

5x=30

x=6

x = 6
PA =16
PB = 32

16/21= AB/42

16*42/21= 32
AB =32
PQ = 42

 *[illustration similar1.png].



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