Question 1206804
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mu = 110.3 = population mean
sigma = 1.7 = population standard deviation


n = 7 = sample size
xbar = sample mean


Compute the z score when xbar = 112
z = (xbar - mu)/( sigma/sqrt(n) )
z = (112 - 110.3)/( 1.7/sqrt(7) )
z = 2.65 approximately when rounding to 2 decimal places


Then use a <a href="https://www.math.arizona.edu/~rsims/ma464/standardnormaltable.pdf">Z table</a> to determine that 
P(Z < 2.65) = 0.99598
which leads to
P(Z > 2.65) = 1-P(Z < 2.65)
P(Z > 2.65) = 1-0.99598
P(Z > 2.65) = 0.00402
This value is approximate.


To get more accuracy you can use a TI84 or similar stats calculator.
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