Question 116112


Let's evaluate {{{f(1)}}}



{{{f(x)=2x^2-3x+5}}} Start with the given function.



{{{f(1)=2(1)^2-3(1)+5}}} Plug in {{{x=1}}}. In other words, replace each x with 1.



{{{f(1)=2(1)-3(1)+5}}} Evaluate {{{(1)^2}}} to get 1.



{{{f(1)=+2-3(1)+5}}} Multiply 2 and 1 to get  2



{{{f(1)=+2-3+5}}} Multiply -3 and 1 to get  -3



{{{f(1)=4}}} Now combine like terms