Question 1206776

Find {{{x}}},


{{{(x-6)/2022 + (x-5)/2023 + (x-4)/2024 = 3}}}


{{{((x-6)*2023*2024 + (x-5)*2022*2024 + (x-4)*2022*2023)/(2022*2023*2024) = 3}}}


{{{(4094552 x - 24567312 + 4092528 x - 20462640 + 4090506 x - 16362024)/8279184144 = 3}}}


{{{12277586 x - 61391976=8279184144 * 3}}}


{{{12277586 x =24837552432+61391976}}}


{{{12277586 x =24898944408}}}


{{{x =24898944408/12277586}}}


{{{x =2028}}}


or, you can find it this way:

{{{(x-6)/2022 + (x-5)/2023 + (x-4)/2024 = 3}}}

if the sum of three terms equal {{{3}}}, then each term must be equal {{{1}}} because {{{1+1+1=3}}}

so,

{{{(x-6)/2022 = 1}}}=>{{{(x-6) = 2022}}}=>{{{x = 2022+6}}}=>{{{x = 2028}}}

{{{(x-5)/2023 = 1}}}=>{{{(x-5) = 2023}}}=>{{{x = 2023+5}}}=>{{{x = 2028}}}

{{{(x-4)/2024 = 1}}}=>{{{(x-4) = 2024}}}=>{{{x = 2024+4}}}=>{{{x = 2028}}}