Question 1206770
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23 = 2(9)+1(5).<br>
To get a partial product of x^23, you need to choose the x^9 term twice and the x^5 term one time, which means you need to choose the constant term 97 times.  Since the coefficients of all the terms are 1, the coefficient of x^23 in the expansion is<br>
{{{100!/((97!)(2!)(1!))=(100*99*98)/2=485100}}}<br>
ANSWER: 485100<br>