Question 1206756
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P(4 or 5) = 4/6 = 2/3<br>
P(other) = 1-2/3 = 1/3<br>
P(first 4 or 5 on 2nd throw) = P((other on 1st throw) AND (4 or 5 on 2nd throw)) = (2/3)*(1/3) = 2/9<br>