Question 1206735


{{{abs(2x - 3)>=1}}}


{{{sqrt(2x - 3)>=1}}}

=>

{{{2x - 3>= 1}}} =>{{{2x >= 1+3}}}=>{{{x >= 4/2}}}=>{{{x >= 2}}}

or

{{{-(2x - 3)>= 1}}}=>{{{-2x+3 >=1}}}=>{{{-1+3 >=2x}}}=>{{{2 >=2x}}}=>{{{2x <=2}}}=>{{{x <=1}}}


solutions:

{{{x <=1}}}

{{{x >= 2}}}


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