Question 1206726
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𝑖 = 20 sin(100𝜋𝑡 + 0.4)
what is the time in milliseconds when the current first reaches its maximum value
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<pre>
It will happen when the argument first time will reach the value of {{{pi/2}}}

   100*pi*t+0.4 = {{{pi/2}}}.


It gives

   t = {{{(pi/2 - 0.4)/(100*pi)}}} = {{{(3.14159265358979/2-0.4)/(100*3.14159265358979)}}} = 0.0037267605.


The dimension is the same as the dimension of "t" in the formula, which (dimension) is not given in the post.
</pre>

Solved.