Question 1206690
{{{log(2,x) + log(4,x )+ log(16,x) = 21/4}}}....change to base {{{10}}}


{{{log(x)/ log(2)+ log(x )/log(4)+ log(x)/ log(16)= 21/4}}}...use common denominator


{{{(log(x)*log(4) *log(16)+ log(x )*log(2) *log(16)+ log(x)*log(2) *log(4))/(log(2)*log(4) *log(16))= 21/4}}}


{{{log(x)*log(4) *log(16)+ log(x )*log(2) *log(16)+ log(x)*log(2) *log(4)= (21/4)(log(2)*log(4) *log(16))}}}

{{{log(x)*log(2^2) *log(2^4)+ log(x )*log(2) *log(2^4)+ log(x)*log(2) *log(2^2)= (21/4)(log(2)*log(2^2) *log(2^4))}}}


{{{log(x)*2log(2) *4log(2)+ log(x )*log(2) *4log(2)+ log(x)*log(2) *2log(2)= (21/4)(log(2)*2log(2) *4log(2))}}}


{{{8((log(2)))^2* log(x)+4((log(2)))^2*log(x)+2((log(2)))^2*log(x)=(21/4)8((log(2)))^3}}}


{{{14(log(2))^2*log(x)=42(log(2))^3}}}...both sides divide by {{{14(log(2))^2 }}}


{{{log(x)=3log(2)}}}


{{{log(x)=log(2^3)}}}...if log same, then


{{{x=2^3}}}


{{{x=8}}}