Question 116135
*[Tex \LARGE (5x+4)^2+7=0] Start with the given equation



*[Tex \LARGE (5x+4)^2=-7] Subtract 7 from both sides




*[Tex \LARGE 5x+4=\pm sqrt{-7}] Take the square root of both sides


*[Tex \LARGE 5x+4=\pm sqrt{7} i] Remember, taking the square root of a negative number does not result in a real number



*[Tex \LARGE 5x=-4\pm sqrt{7} i] Subtract 4 from both sides.




*[Tex \LARGE x=\frac{-4\pm sqrt{7} i}{5}] Divide both sides by 5 to isolate x