Question 1206651
.
The population of J-Town in 2019 was estimated to be 76,500 people with an annual rate of increase of 2.4%.
Part A. Write an equation to model future growth.
Part B. What is the growth factor for J-Town?
Part C. Use the equation to estimate the population in 2072 to the nearest hundred people.
~~~~~~~~~~~~~~~~~~~


<pre>
(A)  P(t) = {{{76500*(1+0.024)^t}}} = {{{76500*1.024^t}}},

     where t are years after 2019  (so 2020 is t= 1,  2021 is t=2  and so on . . . )


(B)  the growth factor is 1.024.


(C)  P(2072) = {{{76500*1.024^(2072-2019)}}} = {{{76500*1.024^53}}} = 268,880.4  (approximately),

     and we say that the population will be about  268,900  to the nearest hundred people in 2072.
</pre>

Solved.


---------------------


To see many other similar and different solved problems on population growth, &nbsp;look into the lesson

&nbsp;&nbsp;&nbsp;&nbsp;- <A HREF=https://www.algebra.com/algebra/homework/logarithm/Population-growth-problems.lesson>Population growth problems</A> 

in this site. &nbsp;The solutions there are given in compact and clear form; &nbsp;to read them is a pleasure.


After reading it, &nbsp;you will be prepared to solve million other similar problems 
on population growth on your own, &nbsp;without any help from outside.


Moreover, &nbsp;after reading this lesson you will be able to teach others to this art.