Question 1206638
Let x be a binomial random variable with n = 7, p = 0.2. 
Find the following value. (Round your answer to three decimal places.)
P(x > 1)
<pre>
It is much easier to calculate P(x=0) and P(x=1) and subtract their sum
from 1:

{{{P(x=0)}}}{{{""=""}}}{{{"C(7,0)"*0.2^0*(1-0.2)^(7-0)}}}{{{""=""}}}{{{(1)(1)(0.8)^7}}}{{{""=""}}}{{{0.2097152}}}
{{{P(x=1)}}}{{{""=""}}}{{{"C(7,1)"*0.2^1*(1-0.2)^(7-1)}}}{{{""=""}}}{{{(7)(0.2)(0.8)^6}}}{{{""=""}}}{{{0.3670016}}}
{{{P(x<=1)}}}{{{""=""}}}{{{P(x=0)+P(x=1)}}}{{{""=""}}}{{{0.2097153+0.3670016}}}{{{""=""}}}{{{0.5767168}}}

{{{P(x>1)}}}{{{""=""}}}{{{1-P(x<=1)}}}{{{""=""}}}{{{1-0.5767168}}}{{{""=""}}}{{{0.4232832}}}

Round to 0.423
 
Edwin</pre>