Question 1206513
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Hi
Gopal had twice as many 50c coins as 20c coins. He also had 5 times as many 10cent coins as 50c coins. If he had $15.40 how many 50c coins did he have,
My son found the solution to have fractions.
Thanks

Let the number of 50c coins be F
Then number of 20c coins = {{{matrix(1,3, (1/2)F, "=", F/2)}}}
Also, number of 10c coins = 5F
Values of the 50c, 20c, and 10c coins = .5F, {{{matrix(1,3, .2(F/2), "=", .1F)}}}, and .1(5F), or .5F, respectively
With TOTAL amount being $15.40, we get: .5F + .1F + .5F = 15.4
                                                   1.1F = 15.4
                             Number of 50c coins, or {{{highlight_green(matrix(1,7, F, "=", 15.4/1.1, "=", 154/11, "=", highlight(14)))}}}</pre>