Question 1206477


A rectangle has a {{{24}}}-foot perimeter. 

{{{2(L+W)=24}}}

{{{L+W=12}}}

if the width is exactly {{{1/2}}} of its length, we have

{{{W=L/2}}}

substitute in

{{{L+L/2=12}}}

{{{3L/2=12}}}

{{{L=24/3}}}

{{{L=8ft}}}


go to {{{W=L/2}}}, substitute{{{ L}}}

{{{W=8ft/2}}}

{{{W=4ft}}}


so, the length {{{L=8ft}}} and width {{{W=4ft}}}


 the area is:

{{{A=L*W}}}

{{{A=8ft*4ft}}}

{{{A=32ft^2}}}