Question 1064005

Find AB by distance formula

A(5,2) B(-3,1)

AB = sqrt((2-1)^2+(5-(-3))^2) =sqrt(65)   Base of triangle

C=(-2,5) , D(-1.52,1.18)

CD = sqrt((-2+1.52)^2+(5-(1.18))^2) =3.85

Area of triangle = 1/2 *8.06*3.85

15.5 unit^2