Question 1206417


Formula for a circle: 

{{{(x-h)^2+(y-k)^2=r^2}}}.....center ( {{{-2}}}, {{{3}}})

The circle is {{{tangent}}} to the {{{y}}}-axis (we know that tangent refers to a line that {{{touches}}} something at exactly one point, we want the circle to have a radius that will make it just big enough to reach the {{{y}}}-axis), hence its radius {{{r=x-coordinate=-2}}}

{{{(x+2)^2+(y-3)^2=(-2)^2}}}

{{{(x+2)^2+(y-3)^2=4}}}


{{{ drawing( 600, 600, -10, 10, -10, 10,
circle(-2,3,.12), locate(-2,3,C(-2,3)),

graph( 600, 600, -10, 10, -10, 10, 3 - sqrt(-x^2-4x), sqrt(-x^2-4x)+3)) }}}