Question 1206401
Find the 4th term of a geometric sequence whose first term is 6 and whose common ratio is 1/3.

a=6 r = 1/3

an= a*r^(n-1)

a(4) = 6*(1/3)^3

a(4) = 6/27

= 2/9

the 4th term of the geometric sequence is 2/9