Question 1206379
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A group of friends went out for lunch. 
Three people ordered soup. Two people ordered sandwiches. 
Each sandwich costs twice as much as a bowl of soup. 
Three people ordered burgers. 
Each burger costs three times as much as a bowl of soup. 
The total cost for their lunch was less than ​$40.48. 
What was the price of a bowl of​ soup?
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<pre>
Let x be the price of a bowl of soup.

Then the price of a sandwich is 2x, and the price of a burger is 3x.


Write an inequality for the total cost 

    3x + 2*(2x) + 3*(3x) < 40.48     (as stated in the problem).


Simplify

    3x + 4x + 9x < 40.48

        16x < 40.48

          x < 2.53.


<U>ANSWER</U>.  The price of a bowl of soup was less than $2.53.
</pre>

Solved.


A little clunky, but that's all what can be done here.