Question 1168236
Write the equation of a circle that satisfies the given conditions:
(a) the center is at (1, -3) and the circle passes through (-3, 5).
(b) the line segment joining A (0, 0), and B (6, -8) is a diameter.
(c) the circle is tangent to y-axis, and the center is at (5, 3)

(a) the center is at (1, -3) and the circle passes through (-3, 5).

Find radius by distance formula.

{{{r= sqrt((1-(-3))^2+(-3-5))^2)}}}

r= sqrt(80)

=4sqrt(5)

Now we have the radius, r, and the center (ℎ,k)~(1,-3) and radius 4sqrt(5)
 We can plug these values into the general equation of a circle:

(x-1)^2+(y+3)^2= (4sqrt(5))^2


(x-1)^2+(y+3)^2= 80