Question 1206376


given: 

{{{x[1]=-4}}} and {{{x[2]=-2}}} 
point ({{{-1}}}, {{{3}}})

using root product equation we have

{{{y=a(x-x[1])(x-x[1]) }}}...plug in given roots and coordinates of given point to calculate {{{a}}}

{{{3=a(-1-(-4))(-1-(-2)) }}}

{{{3=a(-1+4)(-1+2) }}}

{{{3=a(3)(1) }}}

{{{3=3a}}}

{{{a=1}}}

go to

{{{y=a(x-x[1])(x-x[1]) }}}...substitue {{{a}}} and roots

{{{y=1(x-(-4))(x-(-2))}}}

{{{y=(x+4)(x+2)}}}

{{{y=x^2 + 6x + 8}}}

=> answer is C.