Question 115938
{{{((6p-18)/9p)/((3p-9)/(p^2+2p))}}} is what I think you meant.


Remember when dividing one fraction by the other, you invert and multiply, so:


{{{((6p-18)/9p)*((p^2+2p)/(3p-9))}}} 



Then notice that we can do a little factoring:


{{{(2(3p-9)/9p)*(p(p+2)/(3p-9))}}} 
{{{(2(highlight((3p-9)))/9(highlight(p)))*(highlight(p)(p+2)/highlight(3p-9))}}} 
{{{2(p+2)/9}}}
{{{(2p+4)/9}}}