Question 1148373
The coordinates of the vertices of ∆PQR are P (0,5), Q (5,0), and R (10,5).
Determine whether ∆PQR is a right triangle.
Using distance determine if the triangle is an isosceles triangle.
Show All Work

d(PQ) =sqrt((5-0)^2+(0-5)^2) = 5sqrt(2)

d(QR) =sqrt((5-10)^2+(0-5)^2) = 5SQRT(2)

d(PR)=sqrt((0-10)^2+(5-5)^2) =10

Check 

(5sqrt(2))^2+(5sqrt(2))^2=100
sqrt(100)=10 PR is hypotenuse hence right triangle

Two sides are equal so its isoscles triangle