Question 1125543
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The volume of ice-cream in the cone is half the volume of the cone. 
The cone has a 3 cm radius and height of 14 cm. What is the depth of
the ice-cream, correct to 2 decimal places?
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In this problem, there is no need to calculate volumes of the cones.



<pre>
The cone volumes ratio is 2 (the greater to the smaller);

hence, from similarity of the cones, the ratio of heights (greater to smaller) is  {{{root(3,2)}}} = 1.26  (rounded).


So, the depth of the ice-cream is  {{{14/1.26}}} = 11.11 cm.    <U>ANSWER</U>
</pre>

Solved, &nbsp;as simple and in a way as it should be done.


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By the way, the given radius of the greater cone of 3 cm is irrelevant.
This value is excessive, is not necessary, and the problem can be solved without it . . . 


The answer to the question does not depend on the radius of the greater cone
and is the same for any other value of the radius of the greater cone.