Question 1206342
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Answers:
(a) <font color=red size=4>21</font>
(b) <font color=red size=4>72</font>


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Explanation for part (a)


Break things up into three cases:
(1) Exactly zero 'E's are chosen
(2) Exactly one 'E' is chosen
(3) Exactly two 'E's are chosen


Case (1)
The letters to pick from are {S,L,C,T}
There are 4*3 = 12 different two letter words possible where "E" isn't chosen.
Alternatively, you can use the nPr permutation formula with n = 4 and r = 2.
Of course when I say "word", I mean it in quotes because much of these two-letter strings aren't words found in the dictionary.
An example word of case (1) would be SL.


Case (2)
Let's say "E" is in the first slot. There would be 4 words we can form which are: ES, EL, EC, ET
We will also have 4 words with "E" in the second slot.
That's 4+4 = 8 different words that have exactly one "E".
An example word of case (2) would be SE.


Case (3)
This is a trivial case of just one possibility. The word EE.


Add up the results:
12+8+1 = <font color=red>21</font> is the final answer to part (a)


Here is the list of all 21 unique entries (7 rows, 3 columns)
<table border = "1" cellpadding = "5"><tr><td>1</td><td>SE</td><td>SL</td><td>SC</td></tr><tr><td>2</td><td>ST</td><td>ES</td><td>EL</td></tr><tr><td>3</td><td>EE</td><td>EC</td><td>ET</td></tr><tr><td>4</td><td>LS</td><td>LE</td><td>LC</td></tr><tr><td>5</td><td>LT</td><td>CS</td><td>CE</td></tr><tr><td>6</td><td>CL</td><td>CT</td><td>TS</td></tr><tr><td>7</td><td>TE</td><td>TL</td><td>TC</td></tr></table>
The list was generated using this combinatorics calculator
<a href="https://www.mathsisfun.com/combinatorics/combinations-permutations-calculator.html">https://www.mathsisfun.com/combinatorics/combinations-permutations-calculator.html</a>



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Explanation for part (b)


We'll have three cases:
Case (1): Exactly 0 'E's are chosen
Case (2): Exactly 1 'E' is chosen
Case (3): Exactly 2 'E's are chosen
We stop here since we cannot select 3 "E"s.


Case (1)
There are 4 items to pick from in the set {S,L,C,T}
That gives 4*3*2 = 24 ways to form a three-letter word without any "E"s in it.
An example word of case (1) would be SLC.


Case (2)
We have 3 places to put the "E".
Then we have 4*3 = 12 ways to pick the other letters where order matters.
3*12 = 36 ways to form a three-letter word with exactly one "E" in it.
An example word of case (2) would be SEL.


Case (3)
There are 3 slots to choose from for one of these letters {S,L,C,T}
3*4 = 12 ways to form a three-letter word with exactly two "E"s in it.
An example word of case (3) would be SEE.


Add up the results:
24+36+12 = <font color=red>72</font> is the final answer to part (b)


Below is the list of all 72 unique entries.
The list was generated with the previously mentioned link.
The table has 9 rows and 8 columns.
<table border = "1" cellpadding = "5"><tr><td></td><td>1</td><td>2</td><td>3</td><td>4</td><td>5</td><td>6</td><td>7</td><td>8</td></tr><tr><td>1</td><td>SEL</td><td>SEE</td><td>SEC</td><td>SET</td><td>SLE</td><td>SLC</td><td>SLT</td><td>SCE</td></tr><tr><td>2</td><td>SCL</td><td>SCT</td><td>STE</td><td>STL</td><td>STC</td><td>ESL</td><td>ESE</td><td>ESC</td></tr><tr><td>3</td><td>EST</td><td>ELS</td><td>ELE</td><td>ELC</td><td>ELT</td><td>EES</td><td>EEL</td><td>EEC</td></tr><tr><td>4</td><td>EET</td><td>ECS</td><td>ECL</td><td>ECE</td><td>ECT</td><td>ETS</td><td>ETL</td><td>ETE</td></tr><tr><td>5</td><td>ETC</td><td>LSE</td><td>LSC</td><td>LST</td><td>LES</td><td>LEE</td><td>LEC</td><td>LET</td></tr><tr><td>6</td><td>LCS</td><td>LCE</td><td>LCT</td><td>LTS</td><td>LTE</td><td>LTC</td><td>CSE</td><td>CSL</td></tr><tr><td>7</td><td>CST</td><td>CES</td><td>CEL</td><td>CEE</td><td>CET</td><td>CLS</td><td>CLE</td><td>CLT</td></tr><tr><td>8</td><td>CTS</td><td>CTE</td><td>CTL</td><td>TSE</td><td>TSL</td><td>TSC</td><td>TES</td><td>TEL</td></tr><tr><td>9</td><td>TEE</td><td>TEC</td><td>TLS</td><td>TLE</td><td>TLC</td><td>TCS</td><td>TCE</td><td>TCL</td></tr></table>
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