Question 115904
{{{49^x = 7^(x^2-15)}}}
If I copied it right
{{{7^(2x) = 7^(x^2 - 15)}}}
{{{2x = x^2 - 15}}}
{{{x^2 - 2x - 15 = 0}}}
{{{(x - 5)(x + 3) = 0}}}
{{{x = 5}}}
{{{x = -3}}}
check answers
{{{49^x = 7^(x^2-15)}}}
{{{49^5 = 7^(5^2-15)}}}
{{{7^10 = 7^(25-15)}}}
{{{7^10 = 7^10}}}
and
{{{49^-3 = 7^((-3)^2-15)}}}
{{{7^-6 = 7^(9-15)}}}
{{{7^-6 = 7^-6}}}
OK