Question 1206316


{{{sin( x) + sqrt( 2) = - sin( x)}}} on the interval {{{-pi/2 < x < pi/2}}}

{{{sin( x) +sin( x)  = - sqrt( 2)}}}

{{{2sin( x)  = - sqrt( 2)}}}

{{{sin( x)  = - sqrt( 2)/2}}}

{{{x=sin^-1(- sqrt( 2)/2)}}}

{{{x=-pi/4}}}