Question 1206295
zeros,
{{{f(x)=-1(x^2+2x-3)}}}
{{{f(x)=-1(x+3)(x-1)}}}
zeros are -3 and +1.


Vertex is at the exact middle of the two roots, x=-1, the symmetry axis {{{x=-1}}}.


Maximum point (the vertex) is {{{f(-1)=-1(-1+3)(-1-1)=-1(2)(-2)=4}}}.
Range is the real numbers less than or equal to +4.