Question 1206284
<pre>
Before you get bad-mouthed for not asking a question,
I will assume your question is "What is the probability
of getting such a hand?"

The 3 aces can be chose 4C3 ways.
For each of those ways the 2 non-aces can be chosen from 
the 48 non-aces in 48C2 ways.

The number of ways any 5 cards could be chosen is 52C5, 
so the answer is

{{{((4C3)(48C2))/(52C5)}}}.  Work that out.

Edwin</pre>