Question 1206270

{{{-14=3x-y}}}.......eq.1
{{{2y=-8x}}}..........eq.2
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{{{2y=-8x}}}..........eq.2...solve for {{{y}}}
{{{y=-4x}}}..........eq.2a

substitute in eq.1

{{{-14=3x-(-4x)}}}.......eq.1

{{{-14=3x+4x}}}

{{{7x=-14}}}

{{{x=-2}}}


go to eq.2a, substitute{{{ x}}}

{{{y=-4(-2)}}}..........eq.2a

{{{y=8}}}


given lines intersect in point ({{{-2}}},{{{8}}})



{{{drawing(600, 600, -10, 10, -10, 10,
circle(-2,8,.12), locate(-2,8,p(-2,8)),

graph(600, 600, -10, 10, -10, 10, -4x, 3x+14)) }}}