Question 1206249
there are 10 numbers you can choose from.
they are 0,1,2,3,4,5,6,7,8,9.


there are 26 letters you can choose from.
they are a,b,c,d,e,f,g,h,i,j,k,l,m,n,o,p,q,r,s,t,u,v,w,x,y,z


assuming all letters and numbers can be entered more than once, your possible number of entries would be.


first didit = 10
second digit = 26
third digit = 26
fourth digit = 26
fifth digit = 10


total number of possible combination would be 10 * 26 * 26 * 26 * 10 = 10^2 * 26^3 = 1,757,600 possible choices.


to see how this works, make the possible choices less.


allow for 2 numbers per digit and 2 letters per digit.
let the numbers = 1,2
let the letters = a,b
the possible choices would be 2^2 * 2^3 = 4 * 8 = 32
those choices would be:
1AAA1 1AAA2 1AAB1 1AAB2 1ABA1 1ABA2 1ABB1 1ABB2 1BAA1 1BAA2 1BAB1 1BAB2 1BBA1 1BBA2 1BBB1 1BBB2
16 MORE COMBINATIONS WITH 2 AS THE FIRST DIGIT.
TOTAL = 32.
it works the same way with 10 * 26 * 26 * 26 * 10 = 10^2 * 26^3.