Question 1206161
{{{10t+u}}}, the number


"...its product is 12...";
product of its two digits?


{{{tu=12}}}


The digits reversed...
{{{t+10u-(10t+u)=9}}}

-

{{{-9t+9u=9}}}
{{{-t+u=1}}}
{{{highlight_green(u=t+1)}}}


Back to the product of the digits,
{{{t(t+1)=12}}}
{{{3*4=12}}}-----because only need simple factoring
{{{highlight_green(t=3)}}}


The original number, {{{highlight(34)}}}