Question 1206161
A two digit number is such that it's product is 12 and when the digits are reversed the number exceeds the original number by 9, what is the original number?
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Reversing the digits of a 2-digit # changes the value by 9 time the difference between the digits.
---> the difference between the digits = 1.
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U - T = 1
U = T + 1
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U*T = 12
T*(T+1) = 12
Solving gives the number is 34.
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it's = it is