Question 1206148
{{{tan(theta)/(1-cos^2(theta))}}}

use identity: {{{sin^2(theta)=1-cos^2(theta)}}} and {{{tan(theta)=sin(theta)/cos(theta)}}}


={{{(sin(theta)/cos(theta))/sin^2(theta)}}}...simplify


={{{1/(cos(theta)*sin(theta))}}}


={{{(1/cos(theta))(1/sin(theta))}}}... use identity:{{{1/cos(theta)=sec(theta)}}} and {{{1/sin(theta)=csc(theta)}}}


={{{sec(theta)*csc(theta)}}}