Question 1206122
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The given equation is {{{a+1/3a=2}}}.<br>
Square both sides of the equation:<br>
{{{(a+1/3a)^2=2^2}}}
{{{a^2+2/3+1/9a^2=4}}}<br>
Note that the middle term when squaring the left side of the equation is a constant; it contains no variables.  That is the key to solving a problem like this.<br>
{{{a^2+1/9a^2=4-2/3=10/3}}}<br>
Multiply both sides of the equation by 9 to get the expression we want:<br>
{{{9a^2+1/a^2=9(10/3)=30}}}<br>
ANSWER: 30<br>