Question 1206092
<pre>
The other tutor got you here:

{{{ z[3]= expr(175/130) +expr(225/130) i}}}

But don't go to rounded off decimals, 
as they aren't exact answers.

Reduce the fractions instead:

{{{ z[3]= expr(35/26) +expr(45/26) i}}}

Then if you like, you can factor out {{{5/26}}}

{{{z[3]=expr(5/26)(7+9i)}}}

Edwin</pre>