Question 1206054


The three consecutive integers are {{{x}}},{{{ x + 2}}}, and {{{x + 4}}}
 
if six times the sum of the first and the third is {{{8}}} less than {{{10}}} times the second, we have

{{{6(x + x + 4)=10(x+2)-8}}}
{{{6(2x + 4)=10(x+2)-8}}}
{{{12x + 24=10x+20-8}}}
{{{12x + 24=10x+12}}}
{{{12x -10x =12-24}}}
{{{2x =-12}}}
{{{x=-6}}}

than
{{{x+2=-4}}}
{{{x+4=-2}}}

three consecutive integers are: {{{-2}}},{{{-4}}},{{{-6}}}